MATH SOLVE

4 months ago

Q:
# What is an equation bof the line that is perpendicular to y-4=2(x-6);and passes through the point (-3,-5)

Accepted Solution

A:

Answer:y+5=-1/2(x+3)Step-by-step explanation:as perpendicular,compare that given eqn with y-y1=m(x-x1),m1=2then,perpendicular case,m1×m2=-1m2=-1/2now,as the eqn passes through point (-3,-5),we know,y-y1=m(x-x1)then putting value,y+5=-1/2(x+3)