Q:

Use the following excerpt from your printable table of random numbers toestimate the answer to the question below.46370 55170 53480 49126 8921275292 67291 88241 37808 38154What is the probability that a group of 5 random digits will contain at least 2even digits? (Zero is considered an even digit.)Ο7/10Ο3/5Ο4/5Ο9/10​

Accepted Solution

A:
Answer: [tex]\dfrac{9}{10}[/tex]Step-by-step explanation:From the table , the total number of numbers = 10The group of 5 digits contain less than or equal to 2 even digits = 55170i.e. The total group of 5 digits contain at least 2 =[tex]10-1=9[/tex]Now, the probability that a group of 5 random digits will contain at least 2 even digits is given by :-[tex]=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}=\dfrac{9}{10}[/tex] Hence, the probability that a group of 5 random digits will contain at least 2  even digits [tex]=\dfrac{9}{10}[/tex]