MATH SOLVE

3 months ago

Q:
# After having been on the air for more than a decade, Fox's American Idol seemed to be suffering from viewer fatigue. The average number of viewers from the 2011 season through the 2013 season is approximated by f(t) = 32.744e−0.252t (1 ≤ t ≤ 4) where f(t) is measured in millions, with t = 1 corresponding to the 2011 season.† (Round your answers to three decimal places.) (a) What was the average number of viewers in the 2011 season? million viewers (b) What was the average number of viewers in the 2014 season, assuming that the trend continued into that season? million viewers

Accepted Solution

A:

Answer:(a)25.45 million viewers (b) 11.95 million viewers Step-by-step explanation:The average number of viewers from the 2011 season through the 2013 season is approximated by the function:[Tex] f(t) = 32.744*e^{-0.252t}[/tex] (1 ≤ t ≤ 4) where f(t) is measured in millions.t = 1 corresponds to the 2011 season.(a) In 2011, t=1 Average number of viewers in the 2011 season,[Tex] f(1) = 32.744*e^{-0.252*1}[/tex] =25.45 million viewers (b) In the 2014 season, when =4[Tex] f(4) = 32.744*e^{-0.252*4}[/tex] =11.95 million viewers assuming that the trend continued into that season